Word | Frequency | Number of right neighbors | Number of left neighbors | Ratio |
---|---|---|---|---|
In | 866 | 55 | 2 | 27.5000 |
The | 4573 | 289 | 11 | 26.2727 |
It’s | 253 | 21 | 1 | 21.0000 |
We | 693 | 53 | 3 | 17.6667 |
But | 592 | 35 | 2 | 17.5000 |
While | 215 | 14 | 1 | 14.0000 |
It | 889 | 41 | 3 | 13.6667 |
He | 790 | 40 | 3 | 13.3333 |
That | 227 | 13 | 1 | 13.0000 |
For | 205 | 12 | 1 | 12.0000 |
As | 344 | 22 | 2 | 11.0000 |
And | 484 | 32 | 3 | 10.6667 |
So | 280 | 21 | 2 | 10.5000 |
am | 138 | 10 | 1 | 10.0000 |
goes | 70 | 9 | 1 | 9.0000 |
They | 362 | 27 | 3 | 9.0000 |
If you | 89 | 9 | 1 | 9.0000 |
On | 222 | 17 | 2 | 8.5000 |
within | 175 | 8 | 1 | 8.0000 |
She | 335 | 16 | 2 | 8.0000 |
Word | Frequency | Number of right neighbors | Number of left neighbors | Ratio |
---|---|---|---|---|
various | 92 | 1 | 8 | 0.1250 |
part | 341 | 3 | 21 | 0.1429 |
wants | 82 | 1 | 7 | 0.1429 |
such as | 203 | 1 | 7 | 0.1429 |
latest | 106 | 1 | 7 | 0.1429 |
often | 135 | 2 | 13 | 0.1538 |
kind | 126 | 2 | 13 | 0.1538 |
commitment | 51 | 1 | 6 | 0.1667 |
tried | 78 | 1 | 6 | 0.1667 |
towards | 85 | 1 | 6 | 0.1667 |
kind of | 101 | 2 | 12 | 0.1667 |
involved | 114 | 2 | 12 | 0.1667 |
providing | 64 | 1 | 6 | 0.1667 |
isn’t | 67 | 1 | 6 | 0.1667 |
forced | 59 | 1 | 6 | 0.1667 |
be able | 91 | 1 | 6 | 0.1667 |
charged | 52 | 1 | 6 | 0.1667 |
company’s | 182 | 2 | 11 | 0.1818 |
low | 110 | 2 | 10 | 0.2000 |
winning | 60 | 1 | 5 | 0.2000 |
In this subsection, we compute the ratio of the number of right neighbors and the number of left neighbors. Again, we look for words with extreme ratios:
Data for first table:
select word,w.freq,aa.cnt, bb.cnt,aa.cnt/bb.cnt as r from words w, (select w1_id,count(c.w2_id) as cnt from co_n c where w1_id>100 group by w1_id) aa, (select w2_id,count(c.w1_id) as cnt from co_n c where w2_id>100 group by w2_id) bb where w_id=aa.w1_id and aa.w1_id=bb.w2_id order by r desc limit 20;
Diagram data:
select aa.cnt, bb.cnt from (select w1_id,count(c.w2_id) as cnt from co_n c where w1_id>100 group by w1_id) aa, (select w2_id,count(c.w1_id) as cnt from co_n c where w2_id>100 group by w2_id) bb where aa.w1_id=bb.w2_id;
5.1.7.1 Number of NN co-occurrences vs. Frequency I
5.1.7.2 Number of NN co-occurrences vs. Frequency II